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In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be :
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1 G 499 -
499 G 500 -
1 G 500 -
500 G 499
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Correct Option: C
As 0.2% of main current passes through the galvanometer hence 998/1000 current through the shunt. 
 |  | G = | | | S ⇒ S = | ||||
| 1000 | 1000 | 499 |
Total resistance of Ammeter
| R = | = | | | G | = | ||||
| 499 | |||||||||
| S + G | | | + G | 500 | |||||
| 499 | |||||||||
