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					 A galvanometer having a coil resistance of 60 Ω shows full scale deflection when a current of 1.0 amp passes through it. It can be converted into an ammeter to read currents upto 5.0 amp by
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                        - putting in series a resistance of 15 Ω
- putting in series a resistance of 240 Ω
- putting in parallel a resistance of 15 Ω
- putting in parallel a resistance of 240 Ω
 
Correct Option: C
G = 60ω Ig = 1.0A, I=5A. 
Let S be the shunt resistance connected in parallel to galvanometer 
Ig G = (I – Ig) S, 
| S = | = | × 60 = 15 Ω | ||
| I - Ig | 5 - 1 | 
Thus by putting 15Ω in parallel, the galvanometer can be converted into an ammeter.
 
	