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A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 × 10–4 ampere gives a deflection of one per division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of
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- 2450 Ω in series
- 2500 Ω in series.
- 245 Ω in series.
- 2550 Ω in series.
Correct Option: A
Rg = 50Ω, Ig = 25 × 4 × 10–AΩ = 10–2 ARange of V = 25 volts
V = Ig(Re + Rg)
∴ Re = | - Rg = 2450 Ω | |
Ig |