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A bar magnet having a magnetic moment of 2× 104 JT-1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 × 10-4 T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field is
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- 12 J
- 6 J
- 2 J
- 0.6 J
Correct Option: B
Work done
= MB (cos θ1 – cos θ2)
= MB (cos 0° – cos 60°)