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A bar magnet is oscillating in the earth’s magnetic field with a period T. What happens to its period of motion, if its mass is quadrupled
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- motion remains simple harmonic with new period = T/2
- motion remains simple harmonic with new period = 2 T
- motion remains simple harmonic with new period = 4T
- motion remains simple harmonic and the period stays nearly constant
Correct Option: B
The time period of a bar magnet in a magnetic field is given by.
T = 2π√I/MB;
Here, I = moment of inertia ∝ m, M = moment of magnet, B = magnetic field.
T ∝ √I ∝ √m; so, T becomes twice as mass becomes four times.
