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A 6 volt battery is connected to the terminals of the three metre long wire of uniform thickness and resistance of 100 ohm. The difference of potential between two points on the wire separated by a distance of 50 cm will be
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- 1.5 volt
- 3 volt
- 3 volt
- 1 volt
Correct Option: D
R α l
For 300 cm, R = 100 Ω
| For 50 cm, R' - | × 50 = | Ω | ||
| 300 | 3 |
∴ IR = 6
| ⇒ IR' = | 6 | × R' = | 6 | × | 50 | = 1 volt. |
| R | 100 | 3 |
