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Resistances n, each of r ohm, when connected in parallel give an equivalent resistance of R ohm. If these resistances were connected in series, the combination would have a resistance in ohms, equal to
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- nR
- n²R
- R/n²
- R/n
Correct Option: B
| R = | r | ⇒ r = nR |
| n |
When connected in series, Req = nr = n (nR) = n²R
