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Current through 3 Ω resistor is
0.8 amp., then potential drop through 4Ω resistor is
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- 9.6 V
- 2.6 V
- 4.8 V
- 1.2 V
Correct Option: C
Voltage across 3 Ω resistance = 3 × 0.8 = 2.4V
This voltage is the same across 6 Ω resistance.
Hence current through this resistance
| i = | = | = 0.4 amp | ||
| R | 6 |
Total current in the circuit = 0.8 + 0.4 = 1.2 amp
Voltage across 4 Ω resistance = 4 × 1.2 = 4.8 volts
