Power dissipated across the 8Ω resistor in the circuit

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Power dissipated across the 8Ω resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 3Ω resistor is

1. 1.0
2. 0.5
3. 3.0
4. 2.0

Correct Option: C

Power = V . I = I²R

Potential over 8Ω = Ri₂ = 8 x (1/2) = 4V
This is the potential over parallel branch. So,
i₁ = (4/4) = 1A
Power of 3Ω = i₁²R = 1 × 1 × 3 = 3W