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If 25W, 220 V and 100 W, 220 V bulbs are connected in series across a 440 V line, then
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- only 25W bulb will fuse
- only 100W bulb will fuse
- both bulbs will fuse
- none of these
Correct Option: A
As for an electric appliance R = (Vs² / W),so for same specified voltage Vs
R25 | = | 100 | = 4 | |
R100 | 25 |
i.e, R25 = 4R with R100 = R
Now in series potential divides in proportion to resistance.
So, V1 = (R1/R1 + R2)V
i.e., V25 = (4/5) x 400 = 352 V
and V2 = (R1/R1 + R2)V
i.e., V100 = (1/5) x 400 = 88V
From this, it is clear that voltage across 100 W bulb (= 88 V) is lesser than specified(220 V) while across 25 W bulb (= 352 V) is greater than specified (220 V), so, 25 W bulb will fuse.