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Current Electricity

  1. A potentiometer wire has length 4 m and resistance 8Ω. The resistance that must be connected in series with the wire and an accumulator of e.m.f. 2V, so as to get a potential gradient 1 mV per cm on the wire is​
    1. 40 Ω
    2. 44 Ω
    3. 48 Ω ​
    4. ​32 Ω
Correct Option: D

Total potential difference across potentiometer wire ​
= 10–3 × 400 volt = 0.4 volt ​
potential gradient = 1mv/cm ​
= 10–3 v/cm = 10–1(v/3) ​
Let resistance of RΩ connected in series.


⇒​R + 8 = 40  or,​R = 32 Ω



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