For the network shown in the Fig. the value of the current

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For the network shown in the Fig. the value of the current i is

1. 9V/35
2. 18V/5
3. 5V/9
4. 5V/18

Correct Option: D

It is a balanced Wheatstone bridge. Hence resistance 4Ω can be eliminated.

R_eq =	6 x 9	=	18
	6 + 9		5

∴ i =	V	=	5V
	R_eq		18