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In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given respectively by
e = E0 sin ωt
i = I0 sin (ωt – φ)
The average power in the circuit over one cycle of a.c. is
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E0I0 2 -
E0I0 sin φ 2 -
E0I0 cos φ 2 - E0I0
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Correct Option: C
The average power in the circuit over one cycle of a.c. is given by
Pav = erms × irms × cosφ
= | E0 | . | I0 | . cos f = | E0 I0 | cos f |
√2 | √2 | 2 |