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In a region of uniform magnetic induction B = 10–2 tesla, a circular coil of radius 30 cm and resistance π² ohm is rotated about an axis which is perpendicular to the direction of B and which forms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating current induced in the coil is
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- 4π2 mA
- 30 mA
- 6 mA
- 200 mA
Correct Option: C
| I0 = | E0 | = | n B A ω | |
| R | R |
Given, n = 1, B = 10–2 T,
A = π(0.3)2m2, R = π2
f = (200/60) and ω = 2π(200/60)
Substituting these values and solving, we get
I0 = 6 × 10–3 A = 6mA
