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A coil has resistance 30 ohm and inductive reactance 20 ohm at 50 Hz frequency. If an ac source, of 200 volt, 100 Hz, is connected across the coil, the current in the coil will be
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- 4.0 A
- 8.0 A
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20 A √13 - 2.0 A
Correct Option: A
If ω = 50 × 2π then ωL = 20Ω
If ω′ = 100 × 2π then ω′L = 40Ω
Current flowing in the coil is
| I = | 200 | = | 200 | = | 200 | |
| Z | √R² + (ω'L)² | √(30)² + (40)² |
I = 4A.
