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Consider a population of 10,000 individuals, of which 2500 are homozygotes (PP) and 3000 are heterozygotes (Pp) genotype. The frequency of allele p in the population is ______.
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- 3.671
- 0.671
- 5.71
- None of the above
Correct Option: B
We have , according to Hardy -Weinberg's law of population dynamics and equilibrium ,'
P2 + 2PQ + Q2 = 1
Where , P is the allelic frequency of ' p ' .
Now , Total population = 10000
Therefore, P2 = 2500 / 10000 = 0.25
and 2PQ = 3000 / 10000 = 0.3
Therefore, Q2 = 1 – P2 – 2PQ
= 1 – 0.25 – 0.3 = 0.45
So, Q = 0.671 which is the frequency of the allele p .