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Hypophosphatemia is manifested by an X-linked dominant allele.What proportion of the offsprings from a normal male and an affected heterozygous female will manifest the disease?
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- ½ sons and ½ daughters
- all daughters and no sons
- all sons and no daughters
- ¼ daughters and ¼ sons
Correct Option: A
Given, Hypophosphatemia is caused due to X-linked dominant allele. Now, when a normal male (XY) and a diseased female (XHX) are crossed together, the F1 generation will have offspring : XX, XHX, XY and XHY. So from this it can be seen that half of the male offspring and half of the female offspring bear the diseased allele.