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Genetics-i Miscellaneous

  1. Hypophosphatemia is manifested by an X-linked dominant allele.What proportion of the offsprings from a normal male and an affected heterozygous female will manifest the disease? ​​
    1. ½ sons and ½ daughters​
    2. all daughters and no sons
    3. all sons and no daughters​ ​​
    4. ¼ daughters and ¼ sons
Correct Option: A

Given, Hypophosphatemia is caused due to X-linked dominant allele. ​Now, when a normal male (XY) and a diseased female (XHX) are crossed together, the F1 generation will have offspring : XX, XHX, XY and XHY. So from this it can be seen that half of the male offspring and half of the female offspring bear the diseased allele.



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