Direction: A culture of Rhizobium is grown in a chemostat (100 m3 bioreactor). The feed contains 12 g/L sucrose, KS for the organism is 0.2 g/L and µm = 0.3 h–1.
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The flow rate required to result in steady state concentration of sucrose as 1.5 g/L in the bioreactor will be
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- 15 m3 h–1
- 26 m3 h–1
- 2.6 m3 h–1
- 150 m3 h–1
Correct Option: B
By using the Monod Equation under steady state,
We have, µ = µmax [S]/[S] + KS = 0.3 hr–1 * 1.5g/l/ [1.5g/l] + [0.2g/l]
µ = 0.2648 hr–1
D = µ (by using the Monod model)
Also, D = F / V
Therefore, equating the two, we get, F = µV = 0.2648 * 10
F= 26.5 m3hr–1
