-
A room measures 3 m (width) × 4 m (length). The outdoor temperature is 36°C. The volumetric specific heat of air is 1300 J/cu.m.°C. The ventilation heat flow rate in Watts required to attain an internal room temperature of 26°C with 3 air changes per hour is ____________
-
- 190
- 390
- 270
- 90
Correct Option: B
Total volume of room = 3 × 4 × 3 = 36 m3
The amount of air changes in 3 turns per hour = 36 × 3 = 108 m3
Ventilation heat flow rate in Watts = Total energy required
Total energy required (ms∆ t) = Volume of air × Specific Heat × Difference Between Temperature
= 108 × 1300 × 10 = 1404000 Joule
= 1404000 Joule(As Watt (W) = Joule/Sec.) = 390 W
