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A room measuring 5 m × 3.5 m enclosed by brick wall has a ceiling at 3m height. The room has a door and a window opening of l m × 2 m and 1 m × l m respectively. The quantity of plastering required for interior walls (in sqm) is
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- 46.5
- 48
- 51
- 68.5
Correct Option: B
Total surface area = 2[(B × H) + (L × H) +] = 2(15 + 10.5) = 51
The quantity of plastering required for interior walls = TSA-Area of Window opening - Area of Door
= 51 – 1 – 2 = 48 m2