Maximum shear force in the beam will be

Direction: A beam of span Lis simply supported at two ends. One half span of the beam weighs Wand the remaining half span weighs 2W.

R_A + R_E = 3w
R_A × 4 l = w × 3l + 2w × l

R_A =	5	w
	4

Maximum shear in SSB = 1.7 w