Time and Work


  1. Janardan completes 2/3 of his work in 10 days. Time he will take to complete 3/5 of the same work, is









  1. View Hint View Answer Discuss in Forum

    Using Rule 1,

    M1D1
    =
    M2D2
    W1W2

    =
    10
    D2
    2/53/5

    30
    =
    5D2
    23

    ⇒ D2 =
    30
    ×
    3
    = 9 days
    25

    Correct Option: C

    Using Rule 1,

    M1D1
    =
    M2D2
    W1W2

    =
    10
    D2
    2/53/5

    30
    =
    5D2
    23

    ⇒ D2 =
    30
    ×
    3
    = 9 days
    25


  1. A contractor was engaged to construct a road in 16 days. After working for 12 days with 20 labours it was found that only 5/8 th of the road had been constructed. To complete the work in stipulated time the number of extra labours required is :









  1. View Hint View Answer Discuss in Forum

    Using Rule 1,
    Remaining work

    = 1 -
    5
    =
    3
    ;
    88

    Remaining time = 4 days
    M1D1
    =
    M2D2
    W1W2

    =
    20 × 12
    =
    M2 × 4
    5/83/8

    =
    20 × 12
    =
    M2 × 4
    53

    ⇒ 4 × 12 =
    M2 × 4
    3

    ⇒ M2 = 12 × 3 = 36
    ∴ Number of additional workers
    = 36 – 20 = 16

    Correct Option: D

    Using Rule 1,
    Remaining work

    = 1 -
    5
    =
    3
    ;
    88

    Remaining time = 4 days
    M1D1
    =
    M2D2
    W1W2

    =
    20 × 12
    =
    M2 × 4
    5/83/8

    =
    20 × 12
    =
    M2 × 4
    53

    ⇒ 4 × 12 =
    M2 × 4
    3

    ⇒ M2 = 12 × 3 = 36
    ∴ Number of additional workers
    = 36 – 20 = 16



  1. If 12 men working 8 hours a day complete the work in 10 days, how long would 16 men working
    7
    1
    2
    hours a day take to complete the same work?









  1. View Hint View Answer Discuss in Forum

    Using Rule 1,

    ⇒ 16 ×
    15
    × x = 12 × 8 × 10
    2

    ⇒ 8 × 15 × x = 12 × 8 × 10
    ⇒ x =
    12 × 8 × 10
    = 8 days
    8 × 15

    Correct Option: D

    Using Rule 1,

    ⇒ 16 ×
    15
    × x = 12 × 8 × 10
    2

    ⇒ 8 × 15 × x = 12 × 8 × 10
    ⇒ x =
    12 × 8 × 10
    = 8 days
    8 × 15


  1. Jyothi can do
    3
    of a job in 12
    4

    days. Mala is twice as efficient as Jyothi. In how many days will Mala finish the job ?









  1. View Hint View Answer Discuss in Forum

    Using Rule 1,

    ∵ Jyothi can do
    3
    th of a job in 12 days
    4

    ∴ Jyothi can do 1 job in
    12 × 4
    = 16 days
    3

    As Mala is twice as efficient as Jyothi,
    ∴ Mala will finish the job in 8 days

    Correct Option: B

    Using Rule 1,

    ∵ Jyothi can do
    3
    th of a job in 12 days
    4

    ∴ Jyothi can do 1 job in
    12 × 4
    = 16 days
    3

    As Mala is twice as efficient as Jyothi,
    ∴ Mala will finish the job in 8 days



  1. 4 men and 6 women complete a work in 8 days. 2 men and 9 women also complete in 8 days in which. The number of days in which 18 women complete the work is :









  1. View Hint View Answer Discuss in Forum

    According to the question,
    (4 × 8) men + (6 × 8) women ≡ (2 × 8) men + (9 × 8) women
    ⇒ 4 men + 6 women ≡ 2 men + 9 women
    ⇒ (4 – 2) men ≡ (9 – 6) women
    ⇒ 2 men ≡ 3 women
    ∴ 4 men + 6 women ≡ 12 women
    ∴ M1D1 = M2D2
    ⇒ 12 × 8 = 18 × D2

    ⇒ D2 =
    12 × 8
    18

    =
    16
    = 5
    1
    days
    33

    Aliter : Using Rule 1,
    Here, A1 = 4, B1 = 6, D1 = 8
    A2 = 2, B2 = 9, D2 = 8
    A3 = 0, B3 = 18
    Required time
    =
    D1D2(A1B2 - A2B1)
    D1(A1B3 - A3B1) - D2(A2B3 - A3B2)

    =
    8 × 8(4 × 9 - 2 × 6)
    8(4 × 18 - 0 × 6) - 8(2 × 18 - 0 × 6)

    =
    64 × 24
    =
    192
    8 × 72 - 36 × 836

    =
    16
    = 5
    1
    days
    33

    Correct Option: B

    According to the question,
    (4 × 8) men + (6 × 8) women ≡ (2 × 8) men + (9 × 8) women
    ⇒ 4 men + 6 women ≡ 2 men + 9 women
    ⇒ (4 – 2) men ≡ (9 – 6) women
    ⇒ 2 men ≡ 3 women
    ∴ 4 men + 6 women ≡ 12 women
    ∴ M1D1 = M2D2
    ⇒ 12 × 8 = 18 × D2

    ⇒ D2 =
    12 × 8
    18

    =
    16
    = 5
    1
    days
    33

    Aliter : Using Rule 1,
    Here, A1 = 4, B1 = 6, D1 = 8
    A2 = 2, B2 = 9, D2 = 8
    A3 = 0, B3 = 18
    Required time
    =
    D1D2(A1B2 - A2B1)
    D1(A1B3 - A3B1) - D2(A2B3 - A3B2)

    =
    8 × 8(4 × 9 - 2 × 6)
    8(4 × 18 - 0 × 6) - 8(2 × 18 - 0 × 6)

    =
    64 × 24
    =
    192
    8 × 72 - 36 × 836

    =
    16
    = 5
    1
    days
    33