Time and Work


  1. Koushik can do a piece of work in x days and Krishnu can do the same work in y days. If they work together, then they can do the work in









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    Koushik’s 1 day’s work

    =
    1
    x

    Krishnu’s 1 day’s work =
    1
    y

    ∴ One day’s work of both
    =
    1
    +
    1
    =
    x + y
    xyxy

    ∴ Required time =
    xy
    days
    x + y

    Correct Option: C

    Koushik’s 1 day’s work

    =
    1
    x

    Krishnu’s 1 day’s work =
    1
    y

    ∴ One day’s work of both
    =
    1
    +
    1
    =
    x + y
    xyxy

    ∴ Required time =
    xy
    days
    x + y


  1. A and B together can do a piece of work in 36 days, B and C together can do it in 24 days. A and C together can do it in 18 days. The three working together can finish the work in









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    (A + B)’s 1 day’s work =
    1
    36

    (B + C)’s 1 day’s work =
    1
    24

    (A + C)’s 1 day’s work =
    1
    18

    On adding all three,
    2 (A + B + C)’s 1 day’s work
    =
    1
    +
    1
    +
    1
    362418

    =
    2 + 3 + 4
    72

    =
    9
    =
    1
    728

    ∴ (A + B + C)’s 1 day’s work
    =
    1
    16

    ∴ Required time = 16 days

    Correct Option: B

    (A + B)’s 1 day’s work =
    1
    36

    (B + C)’s 1 day’s work =
    1
    24

    (A + C)’s 1 day’s work =
    1
    18

    On adding all three,
    2 (A + B + C)’s 1 day’s work
    =
    1
    +
    1
    +
    1
    362418

    =
    2 + 3 + 4
    72

    =
    9
    =
    1
    728

    ∴ (A + B + C)’s 1 day’s work
    =
    1
    16

    ∴ Required time = 16 days



  1. If 10 men or 20 boys can make 260 mats in 20 days, then how many mats will be made by 8 men and 4 boys in 20 days?









  1. View Hint View Answer Discuss in Forum

    10 men ≡ 20 boys
    ∴ 1 man ≡ 2 boys
    ∴ 8 men + 4 boys
    = (16 + 4) boys = 20 boys
    Hence, 8 men and 4 boys will make 260 mats in 20 days.

    Correct Option: A

    10 men ≡ 20 boys
    ∴ 1 man ≡ 2 boys
    ∴ 8 men + 4 boys
    = (16 + 4) boys = 20 boys
    Hence, 8 men and 4 boys will make 260 mats in 20 days.


  1. 3 men and 4 boys can complete a piece of work in 12 days. 4 men and 3 boys can do the same work in 10 days. Then 2 men and 3 boys can finish the work in number of days is









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    12 (3 men + 4 boys)
    = 10 (4 men + 3 boys)
    ⇒ 36 men + 48 boys
    = 40 men + 30 boys
    ⇒ 4 men = 18 boys
    or 2 men = 9 boys
    ∴ 4 men + 3 boys
    = 21 boys who do the work in 10 days and, 2 men + 3 boys = 12 boys
    ∴ M1D1 = M2D2
    ⇒ 21 × 10 = 12 × D2

    ⇒ D2 =
    21 × 10
    =
    35
    = 17
    1
    days
    1222

    Aliter :
    Using Rule 11,
    Here, A1 = 3, B1 = 4, D1 = 12
    A2 = 4, B2 = 3, D2 = 10
    A3 = 2, B3 = 3
    Required time =
    D1D2(A1B2 - A2B1)
    days
    D1(A1B3 - A3B1) - D2(A2B3 - A3B2)

    =
    12 × 10(3 × 3 - 4 × 4)
    days
    12(3 × 2 - 2 × 4) - 10(4 × 3 - 2 × 3)

    =
    - 120 × 7
    =
    - 840
    =
    70
    =
    35
    = 17
    1
    days
    12 - 60 - 48422

    Correct Option: A

    12 (3 men + 4 boys)
    = 10 (4 men + 3 boys)
    ⇒ 36 men + 48 boys
    = 40 men + 30 boys
    ⇒ 4 men = 18 boys
    or 2 men = 9 boys
    ∴ 4 men + 3 boys
    = 21 boys who do the work in 10 days and, 2 men + 3 boys = 12 boys
    ∴ M1D1 = M2D2
    ⇒ 21 × 10 = 12 × D2

    ⇒ D2 =
    21 × 10
    =
    35
    = 17
    1
    days
    1222

    Aliter :
    Using Rule 11,
    Here, A1 = 3, B1 = 4, D1 = 12
    A2 = 4, B2 = 3, D2 = 10
    A3 = 2, B3 = 3
    Required time =
    D1D2(A1B2 - A2B1)
    days
    D1(A1B3 - A3B1) - D2(A2B3 - A3B2)

    =
    12 × 10(3 × 3 - 4 × 4)
    days
    12(3 × 2 - 2 × 4) - 10(4 × 3 - 2 × 3)

    =
    - 120 × 7
    =
    - 840
    =
    70
    =
    35
    = 17
    1
    days
    12 - 60 - 48422



  1. 2 men and 3 women can do a piece of work in 10 days while 3 men and 2 women can do the same work in 8 days. Then, 2 men and 1 woman can do the same work in









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    2 × 10 men + 3 × 10 women
    = 3 × 8 men + 2 × 8 women
    ⇒ 20 men + 30 women = 24 men + 16 women
    ⇒ 4 men = 14 women or 2 men = 7 women
    ∴ 2 men + 3 women = 10 women
    ∴ 2 men + 1 woman = 8 women
    ∴ M1D1 = M2D2
    ⇒ 10 × 10 = 8 × D2

    ⇒ D2 =
    25
    = 12
    1
    days
    22

    Aliter :
    22 (Using Rule 11),
    Here, A1 = 2, B1 = 3, D1 = 10
    A2 = 3, B2 = 2, D2 = 8
    A3 = 2, B3 = 1
    Required time =
    D1D2(A1B2 - A2B1)
    days
    D1(A1B3 - A3B1) - D2(A2B3 - A3B2)

    =
    10 × 8(2 × 2 - 3 × 3)
    days
    10(2 × 1 - 2 × 3) - 8(3 × 1 - 2 × 2)

    =
    10(2 × 4 - 9)
    days
    10(2 - 6) - 8(3 - 4)

    =
    - 400
    =
    25
    - 322

    = 12
    1
    days
    2

    Correct Option: B

    2 × 10 men + 3 × 10 women
    = 3 × 8 men + 2 × 8 women
    ⇒ 20 men + 30 women = 24 men + 16 women
    ⇒ 4 men = 14 women or 2 men = 7 women
    ∴ 2 men + 3 women = 10 women
    ∴ 2 men + 1 woman = 8 women
    ∴ M1D1 = M2D2
    ⇒ 10 × 10 = 8 × D2

    ⇒ D2 =
    25
    = 12
    1
    days
    22

    Aliter :
    22 (Using Rule 11),
    Here, A1 = 2, B1 = 3, D1 = 10
    A2 = 3, B2 = 2, D2 = 8
    A3 = 2, B3 = 1
    Required time =
    D1D2(A1B2 - A2B1)
    days
    D1(A1B3 - A3B1) - D2(A2B3 - A3B2)

    =
    10 × 8(2 × 2 - 3 × 3)
    days
    10(2 × 1 - 2 × 3) - 8(3 × 1 - 2 × 2)

    =
    10(2 × 4 - 9)
    days
    10(2 - 6) - 8(3 - 4)

    =
    - 400
    =
    25
    - 322

    = 12
    1
    days
    2