8M + 12W = 4 days (whole work)
⇒ 32M + 48W = 1 day ................ (1)
Again 6M + 14W = 5 days
⇒ 30M + 70W = 1 day ................(2)

Correct Option: A

8M + 12W = 4 days (whole work)
⇒ 32M + 48W = 1 day ................ (1)
Again 6M + 14W = 5 days
⇒ 30M + 70W = 1 day ................(2)
From eq. (1) and (2)
32M + 48W = 30M +70W
⇒ 2M = 22W
⇒ 1M = 11W
Now, 30M + 70W = 1 day
(30 X 11 X 70)W = 1 day
Therefore 400W requires 1 day to complete the whole work.
Thus 20W needs 20 days to complete the whole work.

∵ One man alone finishes te work in 100 days.
⇒ 10 men can finish the work in 10 day.
⇒ 15 women can finish work in one days = 1/6 - 1/10 = 1/15 work

Correct Option: D

∵ One man alone finishes te work in 100 days.
⇒ 10 men can finish the work in 10 day.
⇒ 15 women can finish work in one days = 1/6 - 1/10 = 1/15 work
⇒ 15 women finish the whole work in 15 days
∴ 1 women finishes the whole work in = 15 x 15 = 225 days

Work to be done by C = (1 - 7/11) = 4/11
∴ (A + B) : C = 7/11 : 4/11 = 7 : 4

Correct Option: B

Work to be done by C = (1 - 7/11) = 4/11
∴ (A + B) : C = 7/11 : 4/11 = 7 : 4
∴ C's share = Rs. 550 x (4/11) = Rs. 200

Work completed by A + B in one day = 1/6 + 1/3 = 1/2

Correct Option: C

Work completed by A + B in one day = 1/6 + 1/3 = 1/2
∴ Time taken by A + B to complete the work = 2 days.

∵ Work of (Ram + Dilip + Shekhar) for 1 day = 1/20
and work of (Ram + Dilip) for 1 day = 1/30
∴ Work of Shekhar for 1 day = 1 / 20 - 1 / 30 = 1/60

Correct Option: A

∵ Work of (Ram + Dilip + Shekhar) for 1 day = 1/20
and work of (Ram + Dilip) for 1 day = 1/30
∴ Work of Shekhar for 1 day = 1 / 20 - 1 / 30 = 1/60
Hence, Shekhar will complete the work in 60 days.