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In a three-digit number, the digit at the hundred’s place is two times the digit at the unit’s place and the sum of the digits is 18. If the digits are reversed, the number is reduced by 396. The difference of hundred’s and ten’s digit of the number is
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Correct Option: B
Let the number be 100 (2x) + 10y + x = 201x + 10y ....(i)
∴ 2x + y + x = 18
⇒ 3x + y = 18 .....(ii)
When the digits are reversed, number
= 100(x) + 10y + 2x
= 102x + 10y .....(iii)
∴ 201x +10y – 102x – 10y = 396
⇒ 99x = 396 ⇒ x = 4
∴ From equation (i)
3 × 4 + y = 18
⇒ y = 18 – 12 = 6
∴ Required difference = 2x – y = 2 × 4 – 6 = 2
