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74088 = 2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
74088 = 2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
= (2x2) x (3x3) x (7x7) x (2x3x7)
Least number which should be multiplied to 74088 to make it a Perfect square = 2 x 3 x 7 = 42
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In 19683, 19 lies between 2^{3} and 3^{3}, so left digit is 2 and 683 ends with 3, so right digit is 7.
In 19683, 19 lies between 2^{3} and 3^{3}, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
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175760 = 2^{4} x 5 x 13 ^{3}
= 2^{3} x 2 x 5 x 13^{3}
175760 = 2^{4} x 5 x 13 ^{3}
= 2^{3} x 2 x 5 x 13^{3}
To make perfect cube, it must be divided by 2 x 5 = 10
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Total Students =√4356
Total money donated = 4356 rupees
As total students are equal to the sum donated by each student.
Total Students =√4356
= 66
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√y/169= 54/39
⇒ y/169 = (54/39) x (54/39)
√y/169= 54/39
⇒ y/169 = (54/39) x (54/39)
∴ y= (54/39) x (54/39) x 169 = 324