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Sum of distance traveled by them after T hours
6T + 4T = 20 KM
T = 2 hours.
Suppose they will meet after T hours.
Distance = Speed x Time
Sum of distance traveled by them after T hours
6T + 4T = 20 km
T = 2 hours.
So they will meet at 7:00 AM + 2 hours = 9:00 AM
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Speed in Km/hr = Speed in m/sec x 18/5
Speed = (1500/300 ) m/sec
= 5 m/sec
= (5 x 18/5 ) km/hr
= 18 km/hr
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Speed in m/sec = Speed in km/hr x 5/18
Rohit's speed = 10 Km/hr = (10 x 5/18) m/sec = 50/18 m/sec
Time taken to cover 800 m = (800 / (50/18) ) sec
= (800 x 18/50) sec = 288 sec = 4 min 48 sec
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Let the side of the square field be x and the speed of plane be y
x/200 + x/400 + x/600 + x/800 = 4x/y
Let the side of the square field be x and the average speed of plane be y
x/200 + x/400 + x/600 + x/800 = 4x/y
⇒ 25x/2400 = 4x/y
⇒ y =384
∴ Average speed is 384 km/hr
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∵ Time left = (1/3 X 45/60) hr.
= 1/4 hr.
Distance left = 3km
∴ speed required = [3 / (1/4) ] km/hr.
∵ Time left = (1/3 X 45/60) hr.
= 1/4 hr.
Distance left = 3km
∴ speed required = [3 / (1/4) ] km/hr.
= 3 x 4
=12km/hr .