Problems on Ages


  1. Deepak is 4 times as old as his son. four years hence the sum of their ages will be 43 years. How old is deepak's son now ?









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    Let the son's present age be x years
    Then, (x + 4 ) + (4x + 4) = 43

    Correct Option: B

    Let the son's present age be x years
    Then, (x + 4 ) + (4x + 4) = 43
    ⇒ 5x = 35
    ⇒ x = 7 years


  1. A is 20 years older than B. He is also 6 times as old as B.Then the respective age of A and B are ..... and .... years. ?









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    Let the age of B be N years
    According to the question
    ∵ N + 20 = 6N

    Correct Option: A

    Let the age of B be N years
    According to the question
    ∵ N + 20 = 6N
    ∴ N = 4 years
    ∴ A's age = 4 x 6 = 24 years and B's age = 4 years



  1. The respective ages of father and his son are 41 and 16 years. In how many years will the father be twice as old as his son ?









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    Suppose x years later the father will be twice as old as his son.
    ∵ x + 41 = 2 (x + 16)

    Correct Option: B

    Suppose x years later the father will be twice as old as his son.
    ∵ x + 41 = 2 (x + 16)
    ⇒ x = 41 - 32 = 9 years


  1. A is 3 years younger to B, C is two years older then A. Then B's relation to C is ?









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    Let the age of A be (x - 3) years
    ⇒ B's age = x years
    ⇒ C's age = (x - 3) + 2 = x - 1

    Correct Option: C

    Let the age of A be (x - 3) years
    ⇒ B's age = x years
    ⇒ C's age = (x - 3) + 2 = x - 1
    ∴ B's age - C's age = x - (x - 1) = 1 year
    ∴ B is one year older then C.



  1. A is twice as old as B was two years ago. If the difference in their ages be 2 years, find A's age ?









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    Let B;s age 2 years ago be N years
    ∴ A's present age = 2N years

    From question, 2N - (N + 2) = 2

    Correct Option: C

    Let B;s age 2 years ago be N years
    ∴ A's present age = 2N years

    From question, 2N - (N + 2) = 2
    ⇒ N = 4
    ∴ A's age = 2 x 4 = 8 years