Discount


  1. A tradesman marks his goods at 20% above the cost price. He allows his customers a discount of 8% on marked price. Find out his profit %.









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    Suppose C.P. = 100
    On 20% above S.P. = 120

    On discount of 8% = 120 − 120 ×
    8
    100

    New S.P. = 120 −
    48
    = 120 − 9.6 = 110.4
    5

    Gain = 110.4 – 100 = 10.4%
    2nd method to solve this question
    Here, r = 20%, r1 = 8%
    Profit or loss =
    r ×(100 − r1)
    −r1
    100

    Profit or loss =
    20 ×(100 − 8)
    − 8
    100

    Correct Option: B

    Suppose C.P. = 100
    On 20% above S.P. = 120

    On discount of 8% = 120 − 120 ×
    8
    100

    New S.P. = 120 −
    48
    = 120 − 9.6 = 110.4
    5

    Gain = 110.4 – 100 = 10.4%
    2nd method to solve this question
    Here, r = 20%, r1 = 8%
    Profit or loss =
    r ×(100 − r1)
    −r1
    100

    Profit or loss =
    20 ×(100 − 8)
    − 8
    100

    Profit or loss =
    20 × 92
    − 8
    100

    = 18.4 – 8
    Required Profit or loss = 10.4% profit


  1. Two shopkeepers announce the same price of Rs. 700 for a sewing machine. The first offers successive discounts of 30% and 6% while the second offers successive discounts of 20% and 16%. The difference in their selling price is :









  1. View Hint View Answer Discuss in Forum

    For the first shopkeeper,
    Single equivalent discount for two successive discounts of 30% and 6%

    = 30 + 6 −
    30 × 6
    %
    100

    = ( 36 –1.8 ) % = 34.2 %
    ∴  S.P. of sewing machine = ( 100 – 34.2 ) % of Rs. 700

    For the second shopkeeper,
    Single equivalent discount
    = 20 + 16 −
    20 × 16
    %
    100

    = ( 36 – 3.2 )% = 32.8 %
    ∴  S.P. of sewing machine = 700 × ( 100 – 32.8 ) %

    Correct Option: A

    For the first shopkeeper,
    Single equivalent discount for two successive discounts of 30% and 6%

    = 30 + 6 −
    30 × 6
    %
    100

    = ( 36 –1.8 ) % = 34.2 %
    ∴  S.P. of sewing machine = ( 100 – 34.2 ) % of Rs. 700
    = Rs.
    700 × 65.8
    = Rs. 460.6
    100

    For the second shopkeeper,
    Single equivalent discount
    = 20 + 16 −
    20 × 16
    %
    100

    = ( 36 – 3.2 )% = 32.8 %
    ∴  S.P. of sewing machine = 700 × ( 100 – 32.8 ) %
    = Rs.
    700 × 67.8
    = Rs. 470.4
    100

    Required difference = Rs. (470.4 – 460.6) = Rs. 9.8
    Alternate method to find the difference
    Difference between single equivalent discounts = ( 34.2 – 32.8 ) % = 1.4 %
    ∴  Difference of S.P. = Rs.
    700 × 1.4
    = Rs. 9.8
    100



  1. When a discount of 20% is given on a sweater, the profit is 28%. If the discount is 14%, then the profit is









  1. View Hint View Answer Discuss in Forum

    Let the C.P. of sweater be Rs. 100 and its marked price be Rs. x.
    According to the question,

    x ×
    80
    = 128
    100

    ⇒  x ×
    4
    = 128
    5

    Correct Option: D

    Let the C.P. of sweater be Rs. 100 and its marked price be Rs. x.
    According to the question,

    x ×
    80
    = 128
    100

    ⇒  x ×
    4
    = 128
    5

    ⇒  x =
    128 × 5
    = Rs. 160
    4

    When discount = 14%, then
    S.P. of sweater
    = 160 × (100 – 1(4)%
    =
    160 × 86
    = Rs. 137.6
    100

    ∵  C.P. = Rs. 100
    ∴  Profit per cent = 37.6%


  1. A merchant changed his trade discount from 25% to 15%. This would increase selling price by









  1. View Hint View Answer Discuss in Forum

    Let us assume the price of article be Rs. M.

    ∴  S.P. at 25% discount = Rs.
    75M
    = Rs.
    3M
    1004

    S.P. at 15% discount = Rs.
    85M
    = Rs.
    17M
    10020

    Increased Price = Rs.
    17M
    3M
    204

    Increased Price = Rs.
    17M − 15M
    = Rs.
    M
    2010



    Correct Option: C

    Let us assume the price of article be Rs. M.

    ∴  S.P. at 25% discount = Rs.
    75M
    = Rs.
    3M
    1004

    S.P. at 15% discount = Rs.
    85M
    = Rs.
    17M
    10020

    Increased Price = Rs.
    17M
    3M
    204

    Increased Price = Rs.
    17M − 15M
    = Rs.
    M
    2010

    ∴  Percentage increase =
    M
    × 100
    10
    3M
    4

    ∴  Percentage increase =
    M
    ×
    4
    × 100
    103M

    ∴  Percentage increase =
    40
    = 13
    1
    %
    33



  1. A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed the discount of :









  1. View Hint View Answer Discuss in Forum

    Let C.P. be 100
    Marked price = 110
    ∴  p% of 110 = 11

    ⇒  p =
    11 × 100
    = 10%
    100

    2nd method to solve this question.
    Here, loss % = 1%, r = 10%, r1 = p%
    loss % =
    r × (100 − r1)
    − r1
    100

    −1 =
    100 × (100 − p)
    − p
    100

    Correct Option: B

    Let C.P. be 100
    Marked price = 110
    ∴  p% of 110 = 11

    ⇒  p =
    11 × 100
    = 10%
    100

    2nd method to solve this question.
    Here, loss % = 1%, r = 10%, rr1 = p%
    loss % =
    r × (100 − r1)
    − r1
    100

    −1 =
    100 × (100 − p)
    − p
    100

    (–ve sign for loss)
    –100 = 1000 – 10p – 100p
    110p = 1100
    p = 10%
    ⇒  r1 = 10%